Help with syntax problem for get_image_with_alt

(@wyclef)

What is wrong with my syntax on the following line? Trying to pull a random quote, the title and author both work but am having trouble with the get_image_with_alt line.

$quote .= get_image_with_alt('.$rows[$i]['cover'].', get_the_ID(), '');

The full function

function getQuote() {
if(get_field('books', 34)) {
        $rows = get_field('books', 34);
        $row_count = count($rows);
        $i = rand(0, $row_count - 1);

        echo $rows[$i]['sub_field_name'];

        $quote .= '<blockquote>';
        $quote .= get_image_with_alt('.$rows[$i]['cover'].', get_the_ID(), '');
        $quote .= '<div class="quote-holder">';
        $quote .= '<q>“'.$rows[$i]['title'].'”</q>';
        $quote .= '<cite>— '.$rows[$i]['author'].'</cite>';
        $quote .= '</div>';
        $quote .= '</blockquote>';

    }
    return $quote;
}

This topic was modified 2 months ago by wyclef.

Viewing 2 replies - 1 through 2 (of 2 total)

Joy
(@joyously)

2 months ago

You have nested single quotes when you shouldn’t even have quotes around the variable name.

Moderator bcworkz
(@bcworkz)

2 months ago

^^^ Nor the . dot concatenation operators. We don’t know what the $rows data structure contains, nor what get_image_with_alt() is expecting as a parameter, so there still may be other issues, but the outer quotes and dot operators certainly do not belong in the way you’ve used them.

Viewing 2 replies - 1 through 2 (of 2 total)

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Help with syntax problem for get_image_with_alt

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